2q-10=50-10q+q^2

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Solution for 2q-10=50-10q+q^2 equation: 



2q-10=50-10q+q^2

We move all terms to the left:

2q-10-(50-10q+q^2)=0

We get rid of parentheses

-q^2+10q+2q-50-10=0

We add all the numbers together, and all the variables

-1q^2+12q-60=0

a = -1; b = 12; c = -60;
Δ = b2-4ac
Δ = 122-4·(-1)·(-60)
Δ = -96
Delta is less than zero, so there is no solution for the equation

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